Okay you have 2 sum unknow lets call them X+Y
so X+Y=33, 4X=108
Get X by it self then plug it in 4X=108
X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out
The answer is B trust me I know I did that before
He used 11/12 of sugar.
(1) I multiplied the factors and denominators by eachothers denominators
(2) I ended up with the two converted fractions: 8/12 and 3/12. The reason for this step is because if the two fractions have the smae denominator, it helps make it easier to add the fraction.
(3) I added the fractions, getting the sum of 11/12
Good question!
A leg of a right triangle can never be greater then the hypotenuse
this formula will tell you if it's a valid right triangle

the first two question marks are the legs of the triangle while the one after the = is the hypotenuse.
THE STEPS:




ANSWER: