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3 years ago

Plot the point (-3,6). Plot the point (4, -5).

Mathematics

2 answers:

Nuetrik [128]3 years ago

7 0

Answer:

(-3,5)

Step-by-step explanation:

i think?

Feliz [49]3 years ago

3 0

Step-by-step explanation:

Go left 3 and then up 6 then make a dot

Go right 4 thend own 5 then make a dot

I hope this helps

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3 years ago

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A) The lowest score was in third period. B) The highest score was in first period. Eliminate C) On average, first period did bet

Reptile [31]

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3 years ago

Rewrite: 72x3/4<br> please show how you got answer

Alex_Xolod [135]

We have been given the expression

$72 \times \frac{3}{4}$

We can rewrite the expression as $\frac{72\times 3}{4}$

In order to simplify the given expression, we can check if we have any common terms in the numerator and denominator.

We can write the term 72 which is in the numerator as $18\times 4$

Thus, the expression becomes

$\frac{18\times 4\times 3}{4}$

We can see that 4 is common in both numerator and denominator. Hence, we can cancel 4. Thus, we are left with

$18 \times 3\\
=54$

Therefore, we can rewrite the given expression as 54.

8 0

3 years ago

Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.

dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)

Formula used :

→Mid point of two points- $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

→Slope of two points - $\frac{y_2-y_1}{x_2-x_1})$

→Perpendicular of a line = $\frac{-1}{slope of line})$

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = -1

Equation of AB with slope -1 and the coordinates (-1,0) is,

(y – 0) = -1(x – (-1))

y+x=-1………………(1)

Similarly, for AC

Mid point of AC = $(\frac{2+2}{2},\frac{3-3}{2})=(2,0)$

Slope of AC = $\frac{-3-3}{2-2}=\frac{-6}{0}$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = 0

Equation of AC with slope 0 and the coordinates (2,0) is,

(y – 0) = 0(x – 2)

y=0 ………………(2)

By solving equation (1) and (2),

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of CF = -1

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF

(y – 0) = -1(x – (-1))

y+x=-1………………(3)

Similarly, mid point of BC = $(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)$

Slope of AB = $\frac{-3+3}{-4-2}=0$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))

y+3=0

y=-3………………(4)

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)

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3 years ago

What is the area of the semicircle?

mihalych1998 [28]

Here's the link to the answer.. 69.08

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3 years ago