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3 years ago

12-2x=2(x+1). solve for x

Mathematics

1 answer:

Ymorist [56]3 years ago

8 0

<span>12-2x=2(x+1)
12-2x = 2x+2
12-2 = 2x+2x
10 = 4x
x = 10/4
x = 2.5

Hope this helps!</span>

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Digiron [165]

The angles of a triangle add up to 180 degrees

65 + 3x - 10 + 2x = 180
5x + 55 = 180
5x = 180 - 55
5x = 125
x = 125/5
x = 25 <====

m < B = 3x - 10 = 3(25) - 10 = 75 - 10 = 65 <== B is 65 degrees
m < C = 2x......= 2(25) = 50 <== C is 50

8 0

3 years ago

PLEASE HELP ASAP! WILL GIVE BRAINLIEST!!

Art [367]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

10. A random sample of 10 fibers is taken from a collection of 92 fibers that consists of 43 fibers of polymer A, 17 fibers of p

vazorg [7]

Answer:

0.1150 = 11.50% probability that the sample does not contain any fibers of polymer B

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fibers are chosen without replacement, which means that we use the hypergeometric distribution.

92 fibers means that $N = 92$

Sample of 10 means that $n = 10$

No polymeter B which means that $x = 0$

17 fibers of polymeter B which means that $k = 17$

a. What is the probability that the sample does not contain any fibers of polymer B

This is P(X = 0).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,92,10,17) = \frac{C_{17,0}*C_{75,10}}{C_{92,10}} = 0.1150$

0.1150 = 11.50% probability that the sample does not contain any fibers of polymer B

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3 years ago

Can somebody help teach me how to solve quadratic equations? I have no idea what to plug in. Here are some examples of what I ne

guapka [62]

The best method that will work for any quadratic equation is to use the quadratic formula: x = (-b±√(b² - 4ac))/2a, this will work for any quadratic of the form ax² + bx + c = 0.

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sladkih [1.3K]

D. 118 would be the answer

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