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aliina [53]
3 years ago
10

There are 60 apples and then add 59 apples two times . How many apples and there altogether

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

Step-by-step explanation:

59 apples two times = 59 x 2 = 118 apples

Total apples = 118 + 60 = 178 apples

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Simplify 4x+5/6x^2-x-12 subtract 5x/6x^2-x-12
neonofarm [45]
<span>4x+5/6x^2-x-12 - (5x/6x^2-x-12)
= (4x + 5 - 5x)/(</span>6x^2-x-12)
= (-x + 5) / (2x - 3)(3x +4)
<span>
answer

       -x + 5
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</span>  (2x - 3)(3x +4)
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KATRIN_1 [288]

Answer:

C

Step-by-step explanation:

I don't know for sure, but I am pretty sure this is it.

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An Isosceles triangle is shown below. What is the size of angle a°.
Sergeeva-Olga [200]

Step-by-step explanation:

without seeing a picture I'm guessing 45 45, and 90

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A store asked 250 of its customers whether they were satisfied with the service or not. The responses were also classified accor
lara [203]

Answer:

e

Step-by-step explanation:

<u><em>I think your full question is below: </em></u>

<em>A store asked 250 of its customers whether they were satisfied with the service or not. The responses were also classified according to the gender of the customers. We want to study whether there is a relationship between satisfaction and gender. </em>

<em>A meaningful display of the data from this study would be: </em>

<em>(a) side-by-side boxplots </em>

<em>(b) a pie chart </em>

<em>(c) a histogram </em>

<em>(d) a scatterplot </em>

<em>(e) a two-way table</em>

Explain:  two-way frequency table will deal with two variables, between two sets of categorical data. With genders we have two types: man and female, so two - way table are the best option to display your data.

5 0
3 years ago
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

4 0
3 years ago
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