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choli [55]
3 years ago
13

Simplify. 11 3/4 - 8 1/2 A. 3 1/4 B. 3 1/3 C. 4 1/4

Mathematics
1 answer:
Rainbow [258]3 years ago
5 0

Answer:

A

Step-by-step explanation:

11 3/4 - 8 1/2 = 3 1/4

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Solve<br><br> 7x - 2 = 5x + 14
Alexxx [7]

Answer:

8

Step-by-step explanation:

7x - 5x = 14 + 2

2x = 16

x = 16/2

x = 8

4 0
3 years ago
Consider the figure. What is the area of the figure, in square centimeters? ​
Serhud [2]

Answer: The

Step-by-step explanation: First we look at our right angles of the shape, Next you analyze your formula and use it to form your answer(formula: Base X Height).Then for the final step you would multiply 9x5=45.We wouldn't be doing all of them because that would be doing Total Area.

4 0
3 years ago
Read 2 more answers
For problems 29 - 31 the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c
Elan Coil [88]

Answer:

29) discriminant  is positive

30) discriminant  is 0

31) discriminant  is negative

Step-by-step explanation:

the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.

In the graph of question number 29 we can see that the graph intersects the x axis at two points

so the equation has 2 solutions.

When the equation has two solution then the discriminant is positive

In the graph of question number 30 we can see that the graph intersects the x axis at only one point

so the equation has only  1 solution.

When the equation has only one solution then the discriminant is equal to 0

In the graph of question number 30 we can see that the graph does not intersects the x axis  

so the equation has 2 imaginary solutions.

When the equation has two imaginary solutions then the discriminant is negative

3 0
3 years ago
Given that ∠A and ∠B are supplementary, Daisy conjectured that ∠A≅∠B . Which statement is a counterexample to Daisy's conjecture
Nonamiya [84]

I believe the answer is C. 40 and 140.

8 0
3 years ago
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Which quadratic equation has solutions x=8 and x=−1?
andrezito [222]
There are two ways you can do this

Using the formula


{x}^{2}  - (sum \: of \: roots)x + poduct \: of \: roots = 0

{x}^{2}  - (8+-1)x +  - 1 \times 8 = 0


{x}^{2}  - 7x  - 8 = 0


Working backwards


x = 8 \: or \: x =  - 1
\Rightarrow x-8=0  \: or  \: x+1=0

\Rightarrow (x-8)(x + 1)=0
\Rightarrow  {x}^{2}   + x -8x - 8 = 0
\Rightarrow  {x}^{2}  - 7x - 8 = 0
7 0
3 years ago
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