Let us recall parallelogram properties, which states that opposite angles of parallelogram are congruent.
We can see from graph that side US is parallel to TR and measure of angle U equals to measure of angle R, therefore, quadrilateral drawn in our given graph is a parallelogram.
Since we know that opposite sides of parallelogram are congruent. In our parallelogram UT=SR and US=TR.
In our triangle STU and triangle TSR side TS=TS by reflexive property of congruence.
Therefore, our triangles are congruent by SSS congruence.
I Think the answer is 31 because 20-5 is 15 so 36-5 is 31
Answer:
Initial amount;
2110.6
Common ratio;
0.0201
Equation;
![y=2110.6e^{0.0201x}](https://tex.z-dn.net/?f=y%3D2110.6e%5E%7B0.0201x%7D)
Step-by-step explanation:
In this scenario, the month represents the independent variable x while the membership amount represents the dependent variable y.
The analysis is performed in Ms. Excel. The first step is to obtain a scatter plot of the data then finally inserting an exponential trend line to obtain the required equation.
The Ms. Excel output is shown in the attachment below. To obtain the initial amount we substitute x = 0 in the equation. On the other hand, the common ratio is the exponent in the equation.
The answer is <span>$11.43
you type 63.50 into your calculator
then divide it by 100
the times it by 18
and you get 11.43
that is the answer</span>
The return trip was 21.2 hours long.
Step-by-step explanation:
Given,
Speed of plane from US = 212 mph
Speed of plane on return trip = 232 mph
Let,
x be the time taken on return trip.
Time taken from US = x+2
We know that;
Distance = Speed * Time
Distance of plane from US = 212(x+2) = 212x+424
Distance on return trip = 232x
As the distance will be same, therefore,
![232x=212x+424\\232x-212x=424\\20x=424](https://tex.z-dn.net/?f=232x%3D212x%2B424%5C%5C232x-212x%3D424%5C%5C20x%3D424)
Dividing both sides by 20
![\frac{20x}{20}=\frac{424}{20}\\x=12.2\ hours](https://tex.z-dn.net/?f=%5Cfrac%7B20x%7D%7B20%7D%3D%5Cfrac%7B424%7D%7B20%7D%5C%5Cx%3D12.2%5C%20hours)
The return trip was 21.2 hours long.
Keywords: distance, speed
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