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3 years ago

X+8 is atleast 18 solving one step inequalities by adding and. Subtracting

Mathematics

1 answer:

Mamont248 [21]3 years ago

7 0

X + 8 >= 18

(>= means greater than or equal to)

x + 8 - 8 >= 18 - 8
x >= 10

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One hundred rats with mothers that were exposed to high levels of tobacco smoke during pregnancy were put through a simple maze.

Paul [167]

Answer:

The 90% confidence interval for pis (0.7342, 0.8658).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

100 rats mothers, 80 went right. So $n = 100, \pi = \frac{80}{100} = 0.8$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 1.645\sqrt{\frac{0.8*0.2}{100}} = 0.7342$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 1.645\sqrt{\frac{0.8*0.2}{100}} = 0.8658$

The 90% confidence interval for pis (0.7342, 0.8658).

3 0

2 years ago

A model car is 8 inches long and 5.2

Sphinxa [80]

Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.

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2 years ago

An unknown number y is 20 more than an unknown number x. The number y is also x less than 2. The equations to find x and y are s

Scorpion4ik [409]

Add the equations to eliminate x.

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3 years ago

Read 2 more answers

Please help me with this question.

Brilliant_brown [7]

Answer:

V = 972m^3

Step-by-step explanation:

small = lwh = 9(2)(6)

large = lwh = 16(9)(6)

V = 9(2)(6) + 16(9)(6)

V = 108 + 864

V = 972m^3

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2 years ago

What is the ratio representation of the leg rule for this triangle

ValentinkaMS [17]

Answer:

Where's the triangle? Do you have an image?

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2 years ago