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julia-pushkina [17]
3 years ago
9

Sand falls onto a conical pile at the rate of 10 cubic feet per minute. The radius of the pile is always equal to one half it al

titude. How fast is the altitude of the pile increasing when the pile is 5 feet high?​
Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

Either one of these.

Step-by-step explanation:

volumepile=1/3 (PI r^2)h

but r=h/2, so

volume=1/12 PI h^3

dv/dt=10 ft^3/min

but dv/dt=1/12 PI 3h^2 dh/dt

solve for dh/dt

This assumes you mean by "altitude" the height. If you mean altitude as slant height, you have to adjust the fromula

_______________________________________________

given: r = h/2

V = (1/3)π r^2 h

= (1/3)π (h/2)^2 (h)

= (1/12) π h^3

dV/dt = (1/4)π h^2 dh/dt

for the given data ...

10 = (1/4)π(25)dh/dt

dh/dt = 10(4)/((25π) = 1.6/π feet/min

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