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NISA [10]
3 years ago
15

Can you help me please 3-4 please hurry

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer:

3)  m = 18  

4)  p = 2

Step-by-step explanation:

Lera25 [3.4K]3 years ago
3 0

3. m= -18

4. p= 2

just solve for the variables

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Cell phone Plan A costs$70 per month and comes with a free$500 phone. Cell phone Plan Bcosts$50 per month but does not come with
timofeeve [1]

Answer:

25

Step-by-step explanation:

A = 70*M

B = 500 + 50*M

Costing the same means equal, so we have the equation:

70M = 500 + 50M

-50M           -50M

 

20M = 500

20M / 20 = 500 / 20

m- 25 months

5 0
3 years ago
2968 Divided. By. 56. What. Is the answer to this problem please show your work
Sladkaya [172]

Answer:

53

Step-by-step explanation:

i had to use this old method (pic related).

8 0
3 years ago
Find the area of the figure and type your result in the empty box. 4 cm 4 cm​
Vinil7 [7]
4 cm x 4 cm would make a 16 cm area
just multiply 4 and 4 together to get the answer!

16 cm area

please mark the brainliest!
5 0
2 years ago
8. Let X be the number of cars per minute passing a certain point of some road between 8am and 10am on a Sunday. Assume that X h
Lana71 [14]

Answer:

P (3 or fewer) =0.2650

Step-by-step explanation:

Mean = x` = 5

The Poisson distribution formula  is given by

P(X) = e-ˣ` x`ˣ/ x!

The mean is 5 and the X takes the values 0,1,2,and 3 which means 3 or fewer, so we add the probability of all the values of X to get the desired Value of X.

P(3 or fewer ) = e-⁵ (5)³/3!+  e-⁵ (5)²/2! +e-⁵ (5)/1!+e-⁵ (5)⁰/0!

Putting the Values

P (3 or fewer) = 0.006737 . 125 / 6 + 0.006737 . 25 / 2 +0.006737 . 5 / 1 + 0.006737 . 1 / 1

P (3 or fewer) = 0.140374 + 0.08422+ 0.03369 +0.006737

P (3 or fewer) =0.2650

7 0
3 years ago
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with
soldier1979 [14.2K]

The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

<h3>Probability</h3>

a. Distribution

X ~ N (20 , 6)

b. P(x ≤24)

= P[(x - μ ) / σ  (24 - 20) / 6]

= P(z  ≤0.67)

=  0.74857

=0.7486

Hence:

Probability = 0.7486

c. P(21 < x < 26)

= P[(21 - 26)/ 6) < (x - μ  ) / σ   < (24 - 20) / 6) ]

= P(-0.83 < z < 0.67)

= P(z < 0.67) - P(z < -0.)

=  0.74857- 0.2033

= 0.54527

Hence:

Probability =0.54527

d. Using standard normal table ,

P(Z < z) = 66%

P(Z < 0.50) = 0.66

z = 0.50

Using z-score formula,

x = z×  σ +  μ

x = 0.50 × 6 + 20 = 23

23 Christmas cards

Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

Learn more about probability here:brainly.com/question/24756209

#SPJ1

8 0
2 years ago
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