Perpendicular bisector of segment with endpoints -2,0 and 6,12.
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We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA=
. Hence CM=GC+GM=3*
. Now, since GM is normal to AB, we have by the pythagoeran theorem that:
Hence, we calculate from this that AC^2= 28, hence AC=2*
=BC. Thus, the perimeter of the triangle is 2+4*.
Hence, we calculate from this that AC^2= 28, hence AC=2*