Answer:
200 yd²
Step-by-step explanation:
A = 17 yd
B = 15 yd
C = 2 yd
D = 8 yd
b) Area of rectangle = length * width
![\sf Area \ of \ 2 \ triangle = 2* \dfrac{1}{2}* base * height = base* height\\\\](https://tex.z-dn.net/?f=%5Csf%20Area%20%5C%20of%20%5C%202%20%5C%20triangle%20%3D%202%2A%20%20%5Cdfrac%7B1%7D%7B2%7D%2A%20base%20%2A%20height%20%3D%20base%2A%20height%5C%5C%5C%5C)
Area of right triangular prism = Areas of two triangle + area of the upper rectangle + area of middle rectangle + area of below rectangle
= 8 * 15 + 17 * 2 + 15 *2 + 8*2
= 120 + 34 + 30 + 16
= 200 yd²
Answer:
12r/t
Step-by-step explanation:
Lets x = width
length = x + 4 (4 meters longer than wide)
A = L * W
192 = x ( x +4)
192 = x^2 + 4x
x^2 + 4x - 192 = 0
(x +16)(x-12) = 0
x - 12 = 0, x = 12
x + 16 = 0, x = -16
so width x = 12
length = 12 + 4 = 16 (4 meters longer than wide)
answer. J
16
<h2>
Answer:</h2><h2>The partial products of (27) (108) are 216 , 0 , 27.</h2>
Step-by-step explanation:
To find the value of the second partial product 27x108,
Here the multiplicand = 27
The multiplier = 108
The partial products of the multiplication are :
(27) (8) = 0 2 1 6
(27) (0) = 0 0 0
(27) (1) = 2 7
Adding the terms, we get 2916.
The partial products are 216 , 0 , 27.
Answer:
b. y = −0.5x + 5.5
Step-by-step explanation:
Well first we need to find the slope of line CD.
To do that we'll use the following formula,
![\frac{y^2-y^1}{x^2-x^1}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E2-y%5E1%7D%7Bx%5E2-x%5E1%7D)
We'll use the points (1,1) and (3,5)
So y2 is 5 y1 is 1 so 5-1 = 4
3-1 = 2
<u>Slope = 2x</u>
If the slope of line CD is 2x we can cross out choices C and D.
Two lines that are perpendicular to each other have reciprocal slopes,
meaning is the slope of line CD is 2 then its perpendicular lines slope should be -.5.
If the perpendicular line goes through point (-1,6), the y intercept would be, 5.5.
Look at the image below ↓
<em>Thus,</em>
<em>the answer is option b. y = −0.5x + 5.5.</em>
<em>Hope this helps :)</em>