First, you need to knw the keywords to the problem. Depreciate means to diminish or become less, therefore, you are taking away something from a number.
You start off with $24,000.
From 100%, you take away 7%
100% - 7% = 93%
Now you put the 93% in decimal form:
93% = 0.93
Add it into your equation:
f(x) = 24,000(0.93)^10
Therefore, your answer is A.
Answer:
2y
Step-by-step explanation:
gvt vvg gbunibnuj
Choice a:
The order pair given is (<span>1, 3)
y-4x = 3-4(1) = -1
-1 is greater than -6
Therefore, this choice is wrong
Choice b:
</span>The order pair given is (-2, -14)
y-4x = -14-4(-2) = -6
-6 is equal -6
Therefore, this choice is correct
Choice c:
The order pair given is (-1, -9)
y-4x = -9-4(-1) = -5
-5 is greater than -6
Therefore, this choice is wrong
Choice d:
The order pair given is (3, 5)
y-4x = 5-4(3) = -7
-7 is less than -6
Therefore, this choice is correct
Choice e:
The order pair given is (0, -5)
y-4x = -5-4(0) = -5
-5 is greater than -6
Therefore, this choice is wrong
Ah okay so in differential equations you usually want the top variable isolated. To do this, multiply by dt and 2u and you get
![2udu = 2t + { \sec(t) }^{2} dt](https://tex.z-dn.net/?f=2udu%20%3D%202t%20%2B%20%7B%20%5Csec%28t%29%20%7D%5E%7B2%7D%20dt)
Now just integrate both sides. The integral of 2u with respect to u is u². The integral of (2t + sec²(t) with respect to t is t² + ∫sec²(t)dt. The last part is just tan(x) because d/dt(tan(t)) is sec²(t) so just integrating gets us back. Now we have
![{u}^{2} + c = {t}^{2} + \tan(t) + k](https://tex.z-dn.net/?f=%20%7Bu%7D%5E%7B2%7D%20%20%20%2B%20c%20%3D%20%20%7Bt%7D%5E%7B2%7D%20%20%2B%20%20%5Ctan%28t%29%20%20%2B%20k)
Where c and k are arbitrary constants. Subtracting c from k and you get
![{u}^{2} = {t}^{2} + \tan(t) + b](https://tex.z-dn.net/?f=%20%7Bu%7D%5E%7B2%7D%20%20%3D%20%20%7Bt%7D%5E%7B2%7D%20%20%2B%20%20%5Ctan%28t%29%20%20%2B%20b)
Where b is another constant. To find b, just plug in u(0) = -1 where u is -1 and t is 0. This becomes
![1 = \tan(0) + b](https://tex.z-dn.net/?f=1%20%3D%20%20%5Ctan%280%29%20%20%2B%20b)
tan(0) is 0 so b = 1. Take the plus or minus square root on both sides and you finally get
![u = \: { {t}^{2} } + \tan(t) + 1](https://tex.z-dn.net/?f=u%20%3D%20%20%5C%3A%20%7B%20%7Bt%7D%5E%7B2%7D%20%7D%20%20%2B%20%20%5Ctan%28t%29%20%20%2B%201)
But Brainly didn't let me do but juat remember there is a plus or minus square root on the left.
Answer:
The answer is false
Hope this helps !
Mark me brainliest if I'm right :)