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Andrew [12]
2 years ago
12

What is 4/5 of 55? Pls help me

Mathematics
2 answers:
Shtirlitz [24]2 years ago
5 0

Answer:

44 i know that's right let me know

rjkz [21]2 years ago
4 0

Answer:

44

Step-by-step explanation:

You might be interested in
1.
Luba_88 [7]

Hey there!

a = 5 ; b = 2

Option A.

a + b

= 5 + 2

= 7

Option B.

a - b

= 5 - 2

= 3

Option C.

2a + 3b

= 2(5) + 3(2)

= 10 + 6

= 16

Option D.

5a - b

= 5(5) - 2

= 25 - 2

= 23

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

5 0
2 years ago
Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)
Gnom [1K]

Answer: Horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

Step-by-step explanation:

Since we have given that

y=\dfrac{x^2-9}{4x^2+1}

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is 4x^2+1

Now,

4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

y=\dfrac{1}{4}

Hence, horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

8 0
3 years ago
Consider the following system of equations. -10x2-10y2=-300 5x2+5y2=150 Which statement describes why the system has infinite so
scoundrel [369]

Answer:

The equations represent circles that result in the same graph.

Step-by-step explanation:

we have

-10x^{2}-10y^{2}=-300

Divide by -10 both sides

x^{2}+y^{2}=30 -----> equation A

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

and

5x^{2}+5y^{2}=150

Divide by 5 both sides

x^{2}+y^{2}=30 -----> equation B

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

equation A and equation B are equal

therefore

The system has infinite solutions, because the equations represent circles that result in the same graph.

4 0
3 years ago
You are going to make 5 assemblies, where each assembly requires the use of 1 Type A Bolt. You have a container of bolts that co
OverLord2011 [107]

Answer:

Step-by-step explanation:

You are to make 5 assemblies.

Each assembly requires the use of 1 Type A bolt.

To make the 5 assemblies, you need 5 Type A bolts.

The container of bolts has a total of 60 bolts.

The focus - Type A bolts - is 20 out of this 60.

The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3

(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?

- The exact number of Type A bolts you need for the 5 assemblies is 5

1/3 × 5/10 =  5/30 =  1/6 =  0.167

(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:

1/3 × 4/10 = 0.133

1/3 × 3/10 = 0.1

1/3 × 2/10 = 0.067

1/3 × 1/10 = 0.033

1/3 × 0/10 = 0

TOTAL = 0.333

7 0
3 years ago
Pls help<br> me i really am behind
Lemur [1.5K]

Answer:

A

Step-by-step explanation:

(8-3^2)*9-6

8-9*9-6

-1*9-6

-9-6

-15

5 0
2 years ago
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