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valkas [14]
3 years ago
7

Pls helpp Write the expression using exponents. b.b.b = ?

Mathematics
2 answers:
GuDViN [60]3 years ago
8 0
It’s b to the 3rd power or b cubed

B^3
olchik [2.2K]3 years ago
4 0
B^3 so B to third power, or B cubed. So a b with a little 3 at the top right
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PLEASE HELP ME!!!1 <br> What is the value of x?<br><br><br><br> Enter your answer in the box.
pickupchik [31]
2x+2=3x-52
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x=54
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3 years ago
HEEELLLLLPPP MEEEE PLZZZ!!!!
alina1380 [7]

Answer:

For the first one it would be A. x = -3, 4 because they where f(x) and g(x) intersect.

Step-by-step explanation:

For the second one it would be B. Fuction 1 has the larger maximum at (4,1) because the maximum point for Fuction 1 is at (4,1) becuase that the highest point/vertex it goes.

7 0
3 years ago
there are 60 new houses being built in a neighborhood. Last month, 2/3 of them were sold. This month, 2/5 of the remaining house
SIZIF [17.4K]

Sold Last Month: 60 x \frac{2}{3} = 40

Remaining from last month: 60 - 40 = 20

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6 0
3 years ago
CAN SOMEONE HELP ME PLEASE ASAP!?
Andrews [41]

Answer: 69

Step-by-step explanation:

The two angles are a linear pair, which means that they lie on the same line. Therefore, you just have to substract angle 1 with 180.

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5 0
3 years ago
Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°
Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

\angle OQR+\angle ORQ+\angle ROQ=180^o

Now, since the figure already shows that angle m\angle2+\angle ORQ+50^o=180^oNow, since we have established that the base angles m\angle2+m\angle2+50^o=180^owe can now solve the above equation for m<2 as follows:

\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

7 0
1 year ago
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