Answer:
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)
y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
<span> (6y^2 + 4y + 5) – (3 – 7y + y^2)
= </span><span> 6y^2 + 4y + 5 – 3 + 7y - y^2
= 5</span>y^2 + 11y + 2
hope it helps
Answer:
Step-by-step explanation:
Given:
Waiting time = 5 hours.
We need to find the number of minutes for 5 hours.
Solution:
We know that 60 minutes for each hour, so one hour is equal to 60 minutes.
For one hour = 
For five hours = 
Therefore, you will have to wait 300 minutes in a line.
Answer:
Step-by-step explanation:
Start with the given inequality and solve it for x.
First, add 4 to both sides: 5x > 25
Next, divide both sides by 5: x > 5
The solution (set) is x > 5.
