They got it wrong it is actually k=8
Its about 3.14 * 2.5^2 * 13.5 ( using formula V = pi r^2 h)
= 265 in^3 to nearest in^3.
Answer:
Step-by-step explanation:
y = 4 + 6x
Let x = 1
y = 4 + 6(1)
y = 4 + 6
y = 10
Let x = 5
y = 4 + 6*5
y = 4 + 30
y = 34
Let x = 6
y = 4 + 6x
y = 4 + 6*6
y = 4 + 36
y = 40
Let x = 10
y = 4 + 6*10
y = 4 + 60
y = 64
The area of the entire sector of DEF = 60 / 360 * PI * radius^2
sector area = 1 / 6 * 3.14159265... * 20^2
sector area =
<span>
<span>
<span>
209.4395102393
</span>
</span>
</span>
segment area = sector area - triangle DEF Area
triangle DEF Area = (1/2) * 20 * sine 60 * 20
triangle DEF Area = (1/2) * 0.86603 * 400
triangle DEF Area = <span><span><span>(1/2) * 346.412
</span>
</span>
</span>
triangle DEF Area =
<span>
<span>
<span>
173.206
</span>
</span>
</span>
segment area = <span>
<span>
209.4395102393
</span>
-173.206
</span>
segment area =
<span>
<span>
<span>
36.2335102393
</span>
</span>
</span>
segment area =
36.23 m
Source:
http://www.1728.org/circsect.htm
