<span>Combine the logarithms first: log5(4x+3)-log5(x-1). Since it's subtract, divide the two.
log5((4x+3)/(x-1))=2
Make both sides the exponent of five. 5^log5 cancels out.
5^(log5(4x+3/x-1))=5^2
4x+3/x-1=25
Multiply both sides by (x-1) to get rid of it under 4x+3.
(x-1)4x+3/x-1=25(x-1)
4x+3=25x-25
Now subtract 4x from both sides AND add 25 to both sides. This way you'll have all the x's by itself.
28=21x
Divide both sides by 21.
28/21=x
x=1.33333333333...
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Luis is wrong because 8 to the third power is not 24, but is 512. He multiplied 8 by 3 instead of doing 8x8x8, so Luis made an incorrect claim.
I don’t even know sorry I will try and help out next time
Answer:
It's the third option
Step-by-step explanation:
the domain is all the x values
Answer:
There is not enough evidence to support the claim that the true average penetration is at most 50 mils.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 50
Sample mean, = 52.8
Sample size, n = 45
Alpha, α = 0.05
Sample standard deviation, s = 4.5
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Conclusion:
There is not enough evidence to support the claim that the true average penetration is at most 50 mils.