Answer:
(a) 
(b) 
(c) P(X ≤ 1) = 0.6321
(d) P(2 ≤ X ≤ 5) = 0.1286
Step-by-step explanation:
From the given information; Let consider X to be the time between two successive arrivals at the drive-up window of a local bank.
However; If X is regarded as the exponential distribution with λ = 1 which is identical to a standard gamma distribution with ∝ = 1
The objective is to compute the following :
(a) The expected time between two successive arrivals is;



(b) The standard deviation of the time between successive arrivals is;




(c) P(X ≤ 1)
P(X ≤ 1) = 1 - e⁻¹
P(X ≤ 1) = 0.6321
(d) P(2 ≤ X ≤ 5)
P(2 ≤ X ≤ 5) = [1 - e⁻⁵] - [1 - e⁻²]
P(2 ≤ X ≤ 5) = 0.9933 - 0.8647
P(2 ≤ X ≤ 5) = 0.1286
Answer:
20
Step-by-step explanation:
6/x + 2x²
6/3 + 2(3)²
2 + 2(9)
2 + 18
20
Answer:
A.
Step-by-step explanation:
This property states that when three or more are added (or multiplied), the sum (or the ) is the same regardless of the grouping of the (or the multiplicands).
Answer:
see attachement
Step-by-step explanation:
Answer:
1 is 1.5
2. is 15
3 is 0.4
4. is 3
5. is 0.8
6 is 10
Step-by-step explanation:
Good luck!