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Soloha48 [4]
3 years ago
7

I need helppppppp. whats 1/5x30

Mathematics
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

6

Step-by-step

You're welcome!

:)

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The sides of a triangle are 5:8:10 and it's perimeter is 23 cm. find the area of triangle. ​
Tju [1.3M]

Answer:

19.81cm^2

Step-by-step explanation:

To solve this, you need to use Heron's formula. Heron's formula solves for the area of a triangle given 3 sides defined as a, b, and c, as well as the perimeter. In this formula, p is half of the perimeter. The formula is:

sqrt(p*(p-a)*(p-b)*(p-c))

Plugging the values into this formula gives 19.81cm^2.

8 0
3 years ago
If x=5 and y= -4, evaluate this expression: (-2x +10) - (-6x + 5y + 12) + (x +8y - 16)
saul85 [17]

Answer:

The value of the expression is - 5.

Step-by-step explanation:

(-2x +10) - (-6x + 5y + 12) + (x +8y - 16)=

-2x+10+6x-5y-12+x+8y-16=

(-2x+6x+x)+(-5y+8y)+(10-12-16)=

5x+3y-18

if x=5 and y=-4 then

5*5+3*(-4)-18=25-12-18=25-30=-5

7 0
3 years ago
There are 1,760 yards in a mile. How many yards are in 1.65 miles?
velikii [3]

Answer:

2904

Step-by-step explanation:


8 0
3 years ago
The running back for the Bulldogs football team carried the ball 5 times for a total loss of 8 3 4 yards. Find the average chang
aliya0001 [1]

Answer: The average change in field position on each run was 1\frac34 yards.

Step-by-step explanation:

Given: Total loss of field = 8\dfrac34 yards  = \dfrac{35}{5}\text{ yards}

Number of times football team carried the ball  = 5

The average change in field position on each run =  \dfrac{\frac{35}{4}}{5}

=\dfrac{35}{4\times5}\\\\=\dfrac{7}{4}\\\\=1\dfrac34 yard .

The average change in field position on each run was 1\frac34 yards.

4 0
3 years ago
Read 2 more answers
Hi there can anyone help me out with this question I don't know if this answer is right
Soloha48 [4]
Im pretty sure its centimeters 
6 0
3 years ago
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