Answer:
a)
b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
The probability density function of the uniform distribution is:
The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.
This means that .
a. Give a mathematical expression for the probability density function of driving distance.
b. What is the probability the driving distance for one of these golfers is less than 290 yards?
0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards
3n-16<8
3n<24
n<8
............
The expression you would substitute for x is -2y+4. The answer is d.
Answer:
y=1
x=7/4
Step-by-step explanation:
4x + 5y = 12
3x + 4y = 9.25
4x + 5y = 12
12x + 16y =37
-12x -15 y =-36
12x + 16y =37
y=1
x=7/4
Answer and Explanation:
Solution: The operation of concatenation for a set of string on p. and the set is
AB = {XY | X ∈ A and y ∈ B}.
We need to satisfy all these following properties to find out the standard set is closed under concatenation.
1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.
2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.
3- Intersection of two standards set A and B is A∩B is also a regular set member.
4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.
The closure of the regular set is also standard, and the concatenation of traditional sets is regular.