1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
11

Wat is the mixed improper fraction for 50/10=

Mathematics
2 answers:
Lemur [1.5K]3 years ago
5 0
Improper fraction: 50/10=5
Svetlanka [38]3 years ago
3 0
50/10= 5/1 or 5 50/10=5
You might be interested in
If x = − 6 and y = 2 , evaluate the following expression: 2 ( y − 3 x y )
grigory [225]

       \rule{50}{1}\large\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

     <em>If x=-6 and y=2, evaluate 2(y-3xy)</em>

<em />

<em>      </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

  First, We need to simplify the expression by multiplying the parentheses by 2:-

\longmapsto\sf{2y-6xy}

Now , Replace y with 2 and x with -6:-

\longmapsto\sf{2(2)-6(-6)(2)}

Simplifying,

\longmapsto\sf{4-6(-12)}

Further simplifying,

\longmapsto\sf{4+72}

Adding,

\longmapsto\underline{\boxed{\sf{76}}}

<h3 /><h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

8 0
2 years ago
How can you tell whether an ordered pair is a solution of a linear inequality?
sweet-ann [11.9K]

Hello from MrBillDoesMath!

Answer:

Suppose the ordered pair is (x.y). Substitute these values in the linear equality to see if it is true,

Example. Consider the point (7, -4). Is it a solution of the linear inequality

3x < 4y - 9?   Let's check to find out.

Check:

Is  3 (7) < 4 (-4) - 9    true ?

Is    21  < -16     -9 =  -25   ??  

NO!

So (7,-4) is NOT a solution of the linear inequality.


Thank you,

MrB


7 0
3 years ago
This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the perc
Ahat [919]

The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

<h3><u>Solution:</u></h3>

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

<em><u>The percent increase is given as:</u></em>

\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,

\begin{aligned}&\text { percentage increase }=\frac{1272-1200}{1200} \times 100\\\\&\text { percentage increase }=\frac{72}{1200} \times 100=6\end{aligned}

Thus percent increase is 6 %

4 0
2 years ago
What is the area of this parallelogram? A=31 ½Ft²<br> A = 35 ft²<br>A = 47½ ft²<br> A = 66 ½ ft²​
Phoenix [80]

Answer:

A= 47 1/2

Step-by-step explanation:

3 0
2 years ago
You have an allowance of $15.00 this week. You are in a bowling league that costs
Evgen [1.6K]

Answer: $6.50 + $2x ≤ $15.00

7 0
3 years ago
Read 2 more answers
Other questions:
  • Ms. Rao buys a computer, a printer, and a scanner for $2,543. The computer costs $1,502 more than the printer. The printer costs
    15·1 answer
  • How would i do this
    8·1 answer
  • What steps should be taken to calculate the volume of the prism?Check all that apply
    7·1 answer
  • What is the variable "x" in the equation, 7/2=x/2, and why?
    6·1 answer
  • What is the measurement of angle X​
    12·2 answers
  • 46 qt = ?? ozPLEASEE HELP ASAP
    5·2 answers
  • Which triangles are similar?
    14·1 answer
  • If Brian’s brother took the boys to the mall at 11:30 AM and left at 1:45 PM, how much time did the boys spend at the mall?
    7·2 answers
  • Worth 20 points!!!!!
    7·2 answers
  • Help pls!!!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!