B- shot put , is not typical put into a fitness evaluation
Answer: Differentiate density independent factors are factors that don't rely on other sources of help. Like water or sunlight Density Independent limiting factors rely on other sources for help like plants need water and sunlight so they would be limited to them resources if they ever ran out.
Explanation: That is what these are is because resources don't need resources is independent and resources that need other resources in dependent.
The mean for the total cost of the two items is 82. The standard deviation of the total cost of the two items is 14.14214. The probability of finding two random items at this auction with a total price of less than $80 is 0.44377.
<h3>What is a random variable?</h3>
A random variable is a variable with an undetermined value that gives values to each of the results of a statistical experiment.
From the parameters given:
- Let us assume that X represents the random variable that connotes the price of the item during the large auction.
Given that:
- X is normally distributed with a mean of $41 and
- A standard deviation of $10
X
N(μ, σ²)
X
N(41, 10²)
Suppose we made an assumption that Y should denote the total cost of items:
i.e.
Y = X₁ + X₂
Here;

The variance of (Y) is:


= 14.14214
The probability of finding the two random items at the auction with a total price of less than $80 can be computed as:
P(Y < 80)
Since the data is normally distributed,



Recall that:
P(Z < -z) = P(Z > z)
Hence;
= P (Z > 0.1414213)
= 1 - P(Z ≤ 0.1414213)
From the Z tables, the value of Z at 0.1414213 is 0.55623;
= 1 - 0.55623
= 0.44377
Therefore, we can conclude that the probability of finding two random items at this auction with a total price of less than $80 is 0.44377.
Learn more about random variables in probability here:
brainly.com/question/15246027
Answer: See explanation
Explanation:
Real gross domestic product is simply refered to the economic output of a particular country which has been adjusted for price changes as inflation was taken into consideration.
Nominal gross domestic product is the measurement of the gross domestic product of a particular country which makes use of current prices, and isn't inflation adjusted.
The issue that may arise when nominal gross domestic product was used instead of real gross domestic product is that the nominal GDP leads to the inflation of the growth figure in the economy. This is because the nominal GDP doesn't take inflation into effect.
This leads to the misleading of the GDP since there'll be an overstatement of the GDP even though it was actually a rise in the inflation rate for the particular economy.