I don't quite understand the log form you have, but the way to solve logarithms is to convert them to exponents.
log(b) a = c
b^c = a
So....
log(b) x = y
b^y = x
Does that make sense?
1. Rewrite the system:
x+12y=68 (i)
x=8y-12 (ii)
2. Let's substitute the equation (ii) into the equation (i):
x+12y=68
(8y-12)+12y=68
3. Then, you have:
8y-12+12y=68
4. When you clear "y", you have:
20y-12=68
20y=68+12
20y=80
y=80/20
y=4
5. You already have the value of "y". Now, you must substitute this value into the equation (ii):
x=8y-12
x=8(4)-12
x=32-12
x=20
6. Therefore, the result is:
x=20
y=4
This is a way to work it out
Answer:
1236
The first four-digit number where all the digits are different, one being bigger than the one after it.
H = V/B
The base of the prism is given by the expression 2X^2+8x-9
then c)5x+3
