Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Jacob used 1/7 of a liter
of water.
He needs to fill 1/9 of the fish aquarium.
Find how many liters would Jacob need to fill the aquarium
=> Let x = liters of water need to fill the aquarium
=> x/1 = 1/7 divided by 1/9
=> x = 1/7 x 9/1
=> x = 9/7, since this is an improper fraction, let’s convert it to
mixed fraction
=> x = 1 and 2/7
So, Jacob need 1 and 2/7 liter of water to fill the whole aquarium.
Answer:
The answer should be 14/15.
Step-by-step explanation:
The answer is 14/15 because -2/5 and 4/3 with a common denominator turns into -6/15 and 20/15.
Then you add both of them together.
-6/15 + 20/15 = 14/15