Question

the diameter of a cylinder is 8 inches. the height is 12 inches. what is the surface area of the cylinder?

Answer 1

Answer:

402.25

Step-by-step explanation:

fastbridge

Answer 2

Answer:

$\boxed{\boxed{\pink{\tt \leadsto The \ Surface\ Area \ is \ 402.28\ in.^3. }}}$

Step-by-step explanation:

Given that the the diameter of a cylinder is 8 inches. the height is 12 inches. And we need to find its surface area .

Hence here ,

• Height = 12 inches
• Diameter of base = 8 inches

Figure :-

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{4\ in.}}\put(9,17.5){\sf{12\ in.}}\end{picture}$

$\bf\implies TSA_{Cylinder}= 2\pi r ( r + h) \\\\\bf\implies TSA_{Cylinder} = 2\pi \dfrac{8\ in.}{2} \bigg( \dfrac{8\ in.}{2} + 12 in.\bigg)\\\\\bf\implies TSA_{Cylinder} = 2\pi \times 4 ( 4 \ in.+ 12 \ in.) \\\\\bf\implies TSA_{Cylinder}= 8 \times \dfrac{22}{7}\times 16 in.^3 \\\\\bf\implies\boxed{\red{\bf TSA_{cylinder}= 402.28 in.^3}}$

★ Hence the Surface area of the Cylinder is 402.28 in.³ .