Given:
x, y and z are integers.
To prove:
If 
is even, then at least one of x, y or z is even.
Solution:
We know that,
Product of two odd integers is always odd. ...(i)
Difference of two odd integers is always even. ...(ii)
Sum of an even integer and an odd integer is odd. ...(iii)
Let as assume x, y and z all are odd, then is even.
is always odd. [Using (i)]
is always odd. [Using (i)]
is always even. [Using (ii)]
is always odd. [Using (iii)]
is always odd.
So, out assumption is incorrect.
Thus, at least one of x, y or z is even.
Hence proved.
Answer:
1/6
Step-by-step explanation:
There are 6 numbers on a dice
1,2,3,4,5,6
the even numbers are 2,4,6
so there are 3/6 chance of getting an even number
3/6=1/2
5 and 6 are the two numbers greater than 4
so there are 2/6 chance of getting a number greater than 4
2/6=1/3
So for both to happen chance = 1/2 × 1/3
= 1/6
Answer:
The answer is 60
Step-by-step explanation:
if she drove 180 mile in 3 hours, you have to divide 180 by 30 to find the constant rate. 180 divided by 3 is 60
Answer:
(49p2–490p) ÷(p–10)
Step-by-step explanation:
