PLS PLS PLS PLS HELP 15 POINTS

Solve the equation and check your answer. 0.95 t plus 0.05 left parenthesis 100 minus t right parenthesis equals 0.49 left paren

Triss [41]

<h2>Answer:</h2>

The value of t is:

t=48.8889

<h2>Step-by-step explanation:</h2>

We are asked to solve the linear equation in terms of variable t.

The equation is given by:

$0.95t+0.05(100-t)=0.49(100)$

Firstly we will solve the parentheses term in the left and right hand side of the equality as follows:

$0.95t+0.05\times 100-0.05t=49$

Now we combine the like terms on the left side of equality by:

$0.95t-0.05t+5=49\\\\i.e.\\\\0.90t+5=49$

Now we subtract both side of the equation by 5 to get:

$0.90t=44$

Now on dividing both side of the equation by 0.90 we get:

$t=\dfrac{44}{0.90}\\\\i.e.\\\\t=48.8889$

Hence, the value of t is: 48.8889

7 0

3 years ago

Carli made 9 greeting

Leona [35]

Step-by-step explanation:

Shes wrong because she did it in 3 hours which means she would have made 3 cards and not 9.

3 0

3 years ago

The Tennis Club decided to buy T-shirts for its members. Action Sports Apparel quoted the following prices for the T-shirts.

Hatshy [7]

Answer:

C. c(t) = 21 + 12t

Step-by-step explanation:

6 0

2 years ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let <em>Y</em> = the time taken to deliver a pizza.

The random variable <em>Y</em> follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let <em>X</em> = results of a certain blood test.

It is provided that the random variable <em>X</em> follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to <em>z</em>-scores.

The <em>z</em>-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

4 0

3 years ago

The diameter of this beach ball is 12 inches.

OLEGan [10]

904.78 is the amount of air it can hold.

3 0

3 years ago

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