HELP ASAP 100 POINTS!!
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The astronomer has to choose 3 star images out of 8.This is a problem of combinations. This can be expressed as 8C3 i.e. combination of 8 objects taken 3 at a time.
This means, if 8 images are nearby the astronomer will have 56 choices <span>of the three stars.</span>
This means, if 8 images are nearby the astronomer will have 56 choices <span>of the three stars.</span>
Let the width of the table be = x inches
As the length of a table is 16 inches more than its width, so length = x+16
Area of the rectangular table = 720 square inches
Area of rectangle =
and
Neglect the negative value as length and width cannot be negative
So, width = 20 inches
Length = x+16 = 20+16 = 36 inches
Hence, length is 36 inches and width is 20 inches.