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Zarrin [17]
3 years ago
13

A vaccine has 90% probability of being effective in preventing a certain disease. the probability of getting the disease if the

person is not vaccinated is 50%. in certain geographic region, 25% of the people get vaccinated. if a person is selected at random , find the probability that he or she will contract the disease
Mathematics
1 answer:
IgorLugansk [536]3 years ago
4 0
If 25% of the people <em>are</em> vaccinated, then 75% of the people are <em>not</em> vaccinated.  Of those not vaccinated, each has a 50% chance of contracting the disease.  The probability that someone is both not vaccinated and contracts the disease is (0.75)(0.5)=0.375.
The probability that someone is vaccinated and contracts the disease is (0.25)(0.1)=0.025 (it is multiplied by 0.1 because if the vaccine is 90% effective, then there is a 10% chance someone that is vaccinated can contract the disease.
Add these together for the total:  0.375+0.025=0.4
There is a 40% chance that someone chosen at random will contract the disease.
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butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0
3 years ago
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Lunna [17]
The volume for a pyramid is V= \frac{1}{3} Bh, where B is the area of the base and h is the height.  We are given the volume, and the base and height in terms of x.  Our formula then looks like this: 768= \frac{1}{3} (x)( \frac{1}{6} x).  Simplifying the right side we have 768= \frac{1}{18}  x^{2}.  Multiply both sides by 18 to get rid of the fraction and we have 13824= x^{2}, so x = 117.575
5 0
3 years ago
The sum of the squares of two numbers is 18. the product of the two numbers is 9. find the numbers.
zhuklara [117]
A graph shows the two numbers are either (3, 3) or (-3, -3).

4 0
3 years ago
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Anestetic [448]

Answer:

Forced need to stretch 1414 inches = 129830.91 pounds

Step-by-step explanation:

Force ∝ Distance

F = KD where K is constant of proportionality

K = F/D = 6060/66 = 91.818182

Hence Force needed to stretch 1414 inches =

F = 6060/66 x 1414 = 129830.91 pounds

8 0
3 years ago
(5)^2 - (-9)^2 / (5) - (-9)
timama [110]
89/5
Alternative form

1) 17.8
2)17 4/5
4 0
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