Answer:
Step-by-step explanation:
Use the identity 
where 
and 
.
This results in 
From the unit circle we know that 
and 
Substitute
Simplify
Answer:
In 11 years
Step-by-step explanation:
To calculate the number of years it will take to depreciate to that value, we use the equation below; The amount after t years, with initial amount I at percentage of depreciation d can be represented as follows;
A = I( 1 - d)^t
In the question Using our definition, A = $8,500, I = $22,000, d = 8.5% = 8.5/100 = 0.085 and t = ?
Let’s plug these values;
8,500 = 22,000(1 - 0.085)^t
8,500 = 22,000(0.915)^t
divide both side by 22,000
8,500/22,000 = (0.915)^t
0.3864 = (0.915)^t
Taking the logarithm of both sides
log 0.3864 = log(0.915)^t
log 0.3864 = tlog 0.915
t = log 0.3864/log 0.915
t = 10.7 approximately 11 years
For these problems we need to distribute first and then combine like terms. We can add anything with an "x" together and anything without an "x" together.
Problem 1:
2(x-1)+3(x+2)
2x - 2 + 3x + 6
Answer: 5x + 4
Problem 2:
(4y-3)-2(y-5)
4y - 3 - 2y + 10
Answer: 2y + 7
Answer: 42.6% or you can round it to 43%
Step-by-step explanation:
Answer:
The needed line equation is : x + y + 2 = 0
Step-by-step explanation:
The slope m of the given line equation = -1
The points through which the line passes is (1,-3).
Now,as we know:
The POINT SLOPE form of the equation with point (x0,y0) is given as:
y - y0 = m (x-x0)
So, the equation if line q=with m = -1 and (x0,y0) = (1,-3) is given as
y - (-3) = -1( x - 1)
or, y + 3 = 1 -x
or, x + y + 2 = 0
Hence, the needed line equation is : x + y + 2 = 0
