Answer:
for #2 I'm pretty sure he makes $10 per hour
Make a change of coordinates:


The Jacobian for this transformation is

and has a determinant of

Note that we need to use the Jacobian in the other direction; that is, we've computed

but we need the Jacobian determinant for the reverse transformation (from

to

. To do this, notice that

we need to take the reciprocal of the Jacobian above.
The integral then changes to

Any number to the power 0 is 1.
So 10^0 = 1
- 16:10
- 24:15
- 40:25
8:5 is just a simplier version of these other ratios
Answer: x equals 5
Step-by-step explanation: