Step-by-step explanation:
(2b-3)/(b-2)(b+2) = 3b(b-2)/(b+2)(b-2)
2b²+4b-3b-6/b²-4=3b²-6b/b²-4
2b²+b- 6= 3b²-6b
move square to square unknown to unknown
-b²+7b-6/b²-4
i also dk this is true or false
Answer:
463833
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Medium
Solution
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In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
Answer:
7.4
Step-by-step explanation:
Gud luck on the rest of your school work :)
If a set of exam scores forms a symmetrical distribution, then the student mean scores is the median and the mode too.
<h3>What is a Symmetrical distribution?</h3>
A symmetrical distribution by definition is the situation which occurs when the values of variables appear at regular frequencies and is characterized by the mean, median, and mode all occuring at the same point in most cases.
Graphically, symmetrical distributions may appear as a normal distribution (i.e., bell curve).
Read more on Symmetrical distribution;
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