It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.
In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x
2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y
now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5
now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0
and now we have solved the problem. x=0 and y=-5
Answer:
103,000
Step-by-step explanation:
Use your knowledge of decimal arithmetic. Or, use a calculator.
100,000(1 +.03) = 100,000·1.03 = 1000·103 = 103,000
Answer:
this is my attempt, it might not be right, so please dont be mad if wrong
Step-by-step explanation:
27 * x^3 = 6561x-5 , 49x + 1 = 117649x-2
Answer:
15
Step-by-step explanation:
Regina: 6.5h
Phil: 3(2.5h+5)
When you plug in the number of hours, you get the weekly pay. In order to get the same weekly pay, set the equations equal to each other.
6.5h=3(2.5h+5), This is an equation to find the number of hours it will take for them to get equal pay. Now, simplify.
6.5h=7.5h+15
-h=15
h=-15, -15 hours is your answer. You can't work negative hours though which means that Regina and Phil will never be able to make the same amount.
Phil has a higher rate and starting value, this means that Regina will never make the same amount working the same hours.
