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sesenic [268]
3 years ago
7

Which situation describes a car that can travel $40 miles per gallon of gasoline?

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

A car can travel 80 miles on 2 gallons of gasoline.

Step-by-step explanation:

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A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen
creativ13 [48]

Answer:

Pr = 0.4286

Step-by-step explanation:

Given

Let

U \to\\ Undergraduates

G \to Graduates

So, we have:

U = 3; G =5 -- Total students

r = 4 --- students to select

Required

P(U =2)

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

^nC_r = \frac{n!}{(n-r)!r!}

So, we have:

Total = ^{U + G}C_r

Total = ^{3 + 5}C_4

Total = ^8C_4

Total = \frac{8!}{(8-4)!4!}

Total = \frac{8!}{4!4!}

Using a calculator, we have:

Total = 70

The number of ways of selecting 2 from 3 undergraduates is:

U = ^3C_2

U = \frac{3!}{(3-2)!2!}

U = \frac{3!}{1!2!}

U = 3

The number of ways of selecting 2 from 5 graduates is:

G = ^5C_2

G = \frac{5!}{(5-2)!2!}

G = \frac{5!}{3!2!}

G =10

So, the probability is:

Pr = \frac{G * U}{Total}

Pr = \frac{10*3}{70}

Pr = \frac{30}{70}

Pr = 0.4286

5 0
2 years ago
Solve. 54 ÷ (4 – 1)3
pshichka [43]
54 divide 3*3=54 is the answer
3 0
3 years ago
Read 2 more answers
Yoshi bought new markers. Each package he bought had 8 markers. He used 7 markers and had 25 markers left. How many packages of
Olenka [21]
If Yoshi has 8 per pack and used 7 he would have 32 markers in all and bought 3 packs and had an extra marker
3 0
2 years ago
Read 2 more answers
In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and segment DF is congruent to segment BD . Point C is the point of intersection betw
Rzqust [24]

Answer:

Step-by-step explanation:

Given:

∠DCE ≅ ∠DEC

∠B ≅ ∠F

DF ≅ BD

To prove:

ΔABC ≅ ΔGFE

Solution:

                  Statements                            Reasons

1). ∠DCE ≅ ∠DEC                                1). Given

2). ∠ACB ≅ ∠GEF                               2). Vertically opposite angles to the

                                                                 congruent angles.

3). ∠B ≅ ∠F                                         3). Given

4). DB ≅ DF                                         4). Given

5). DC + CB ≅ DE + EF                       5). Segment addition postulate

6). DC ≅ DE                                        6). Property of isosceles triangle

7). CB ≅ EF                                         7). Transitive property

8). ΔABC ≅ ΔGFE                              8). ASA property of congruence

4 0
2 years ago
How to determine if x and y values represent a function?
SpyIntel [72]

Answer: set up the relation as a table or ordered pairs

Step-by-step explanation: the domain has to be matched with exactly one element in the range.

8 0
2 years ago
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