C. A una pecera se le agregan 9000 cm de agua. ¿Hasta dónde llegará? ¿Cómo lo saben?

HELP ME PLEASE HURRY: Wade has claims that quadrilateral ABCD is a square because he has found that all four sides are congruent

RUDIKE [14]

Answer:

At first we should know that:

The properties of the square are:

It has four equal sides.
All angles are right angles or equal to 90º.
The sum of its all angles is 360º
It has two pairs of perpendicular lines.
It has two pairs of parallel lines.

The properties of Rhombus

It has equal four sides.
The opposite sides are of the same length.
It has two acute angles and two obtuse angles.
The sum of its all angles is 360º
It has zero pairs of perpendicular lines.
It has two pairs of parallel lines.

So, Wade is incorrect because the quadrilateral may be Rhombus

And the quadrilateral to be a square, she needs to show that It has two pairs of perpendicular lines.

6 0

2 years ago

What’s is the value for X+8=12

Luba_88 [7]

Answer:

4

Step-by-step explanation:

X+8= 12

Carry over the 8 and make X the subject.

X= 12-8

X= 4

3 0

3 years ago

Read 2 more answers

A machine stamps 3600 metal parts in 12 minutes. Find the unit rate in parts per minute.

Studentka2010 [4]

Answer:

300

Step-by-step explanation:

you just divide the number of parts by minutes. In this case, 3600/12=300. There's your answer

5 0

3 years ago

Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi

maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is $x=\frac{-31+29}{2}=-1$

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is $y=\frac{8+-10}{2}=-1$

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed $\frac{2}{3}$ of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is $x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11$

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is $x=\frac{(8)(1)+(-1)(2)}{2+1}=2$

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

3 0

3 years ago

A system of linear equations is given by the graph. Okie what is the system shown?

SVETLANKA909090 [29]

Answer:

I think the answer is A.

Step-by-step explanation:

all of the other ones dont seem to line up with the graph.

6 0

3 years ago

Read 2 more answers