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3 years ago

Susan determined that the expression below is equal to 7.59

2 answers:

7 0

Answer: B

Explanation: In order to confirm this you could do the inverse operation so you would do 8.32+7.59 and if you get 15.91 it would be correct.

Liula [17]3 years ago

6 0

The answer is B hope this helps

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Grace has a segment with endpoints A(3, 2) and B(6, 11) that is partitioned by a point C such that AC and BC form a 2:3 ratio. S

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Answer: 2/5

Step-by-step explanation:

In the attachment

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3 years ago

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HELP ME PLEASE ASAP!!!!!!!!

sergij07 [2.7K]

Answer:

(2, 14), (3, 7)

Step-by-step explanation:

The way these angles are numbered, corresponding angle numbers differ by 4, 8, or 12.

Corresponding angles are ...

Angle 2 and Angle 14 . . . . . . numbers differ by 12

Angle 3 and Angle 7 . . . . . . . numbers differ by 4

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If a given angle is Northwest of the intersection, any corresponding angle will also be Northwest of its intersection. Corresponding angles are ...

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3 years ago

Davian is traveling at a constant speed of 85 kilometres per hour. If he is half way through his 510 kilometre trip, how much lo

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E.5 hours
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Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in s

vagabundo [1.1K]

Answer:

y = -0.2x - 5.8

Step-by-step explanation:

If a line is given in the form y = mx + b, the "m" is the slope.

For the line given y = 5x, the slope is 5

The line that is perpendicular to this will have slope that is "negative reciprocal of that".

So, the perpendicular line will have slope of $-\frac{1}{5}$

So, the Perpendicular Line will have equation:

y = -1/5x + b

Let's find b by replacing x with 6 and y with -7 [the point given]. So we have:

$y=-\frac{1}{5}x+b\\-7=-\frac{1}{5}(6)+b\\-7=-\frac{6}{5}+b\\b=-7+\frac{6}{5}\\b=-5.8$

So the equation of perpendicular line = y = -0.2x - 5.8

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago