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soldier1979 [14.2K]
3 years ago
7

Susan determined that the expression below is equal to 7.59

Mathematics
2 answers:
svlad2 [7]3 years ago
7 0
Answer: B

Explanation: In order to confirm this you could do the inverse operation so you would do 8.32+7.59 and if you get 15.91 it would be correct.
Liula [17]3 years ago
6 0
The answer is B hope this helps
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The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

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Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

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