Answer:
432 people on Friday and 658 on Saturday
Step-by-step explanation:
Lets use variables for each day
x=Friday and y=Saturday
now write two equations since you were given two different information (money and people)
$6 on Friday and $8 on Saturday with a total amount of $7856
the equation will be 6x+8y=7856
now the second equation will be for people
x amount of people on Friday and y amount of people on saturday for a total of 1090; the equation will be
x+y=1090
put them together
6x+8y=7856
x+y=1090
now you can cancel a variable but manipulating one of the equations. We'll use x, to cancel x you need make it zero so multiply the bottom by -6
6x+8y=7856
-6(x+y=1090)
6x+8y=7856 now subtract downwards, with the x cancelling
-6x-6y=-6540
2y=1316 simplify
(2y/2)=(1316/2)
y=658
insert y into x+y=1090
x+(658)=1090
-658 -658
x=432
Answer:
-1
Step-by-step explanation:
QUESTION 1
The given expression is
The greatest common factor is 
.
We factor to obtain;
QUESTION 2
The given quadratic equation is
We split the middle term to obtain
Factor by grouping;
Use zero product property;
QUESTION 3
The given system of equation is
If we multiply by 3, we obtain;
If we multiply by 4 we obtain;
Adding the last two equations will give us;
The y-variable is eliminated.
Answer:Multiply 3x+4y=−8
by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.
Answer:
The compound interest is Rs8275
Step-by-step explanation:
The rule of the compound interest is A = P
, where
- r is the interest rate in decimal
- n is the number of periods
The interest I = A - P
∵ The amount of investment is Rs25000 for 3 years
∴ P = 25000
∴ t = 3
∵ The rate of interest is 10% per annum, compounded annually
∴ r = 10% = 10 ÷ 100 = 0.1
∴ n = 1 ⇒ compounded annually
→ Substitute these value in the 1st rule above to find the new amount
∵ A = 25000
∴ A = 25000
∴ A = Rs33275
→ Use the 2nd rule above to find the interest
∵ I = 33275 - 25000
∴ I = 8275
∴ The compound interest is Rs8275
Answer:
Step-by-step explanation:
Part 1:
Let
Q₁ = Amount of the drug in the body after the first dose.
Q₂ = 250 mg
As we know that after 12 hours about 4% of the drug is still present in the body.
For Q₂,
we get:
Q₂ = 4% of Q₁ + 250
= (0.04 × 250) + 250
= 10 + 250
= 260 mg
Therefore, after the second dose, 260 mg of the drug is present in the body.
Now, for Q₃ :
We get;
Q₃ = 4% of Q2 + 250
= 0.04 × 260 + 250
= 10.4 + 250
= 260.4
For Q₄,
We get;
Q₄ = 4% of Q₃ + 250
= 0.04 × 260.4 + 250
= 10.416 + 250
= 260.416
Part 2:
To find out how large that amount is, we have to find Q₄₀.
Using the similar pattern
for Q₄₀,
We get;
Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹
Taking 250 as common;
Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)
= 2501 − 0.04401 − 0.04
Q₄₀ = 260.4167
Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.
Part 3:
From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.
