Help i need to finish it today And can you explain the steps so i wont need help next time or if you don’t want to its okay :)

Which is an example of an internal conflict in literary analysis? Rebecca wanted to sing in the talent show, but she was too shy

rosijanka [135]

Answer:

Rebecca

Step-by-step explanation:

4 0

2 years ago

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Need a quick answer please

Romashka [77]

Step-by-step explanation:

S is equal to Q

Q= 48.5

there are two angels (S,Q). They equal 48.5

so 48.5x2= 97

all angels together (QRSP) equals 360

you can take the 97 and subtract it from the 360 =263

divide 263 to get the angels for P and R

S= 48.5

Q=48.5

R=131.5

P=131.5

8 0

3 years ago

SOMEONE PLZZZ HELP THIS IS DUE IN 2 MINSSS

nydimaria [60]

Answer:

D, and C sorry if I'm wrong

5 0

3 years ago

For the hypotheses below test alpha = 0.025 with n = 100 and bar p = 0.67. State

I am Lyosha [343]

Answer:

Part a : Critical value

For this case we want a value of $\alpha = 0.025$ we need to find on the normal standard distribution a z score that accumulates 0.025 of th area on the left and this value is $z_{crit}= -1.96$

Part b: Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.67 -0.76}{\sqrt{\frac{0.76(1-0.76)}{100}}}=-2.107$

Part c: Statistical decision

$n \hat p= 100*0.67= 67 >5$

$n (1-\hat p)= 100*(1-0.67)= 33 >5$

So then the normal approximation makes sense.

Since the calculated value is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level provided and we can conclude that the true proportion is lower than 0.76

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

$\hat p=0.67$ estimated proportion of interest

$p_o=0.76$ is the value that we want to test

$\alpha=0.025$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.76:

Null hypothesis: $p\geq 0.76$

Alternative hypothesis: $p < 0.76$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a : Critical value

For this case we want a value of $\alpha = 0.025$ we need to find on the normal standard distribution a z score that accumulates 0.025 of th area on the left and this value is $z_{crit}= -1.96$

Part b: Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.67 -0.76}{\sqrt{\frac{0.76(1-0.76)}{100}}}=-2.107$

Part c: Statistical decision

$n \hat p= 100*0.67= 67 >5$

$n (1-\hat p)= 100*(1-0.67)= 33 >5$

So then the normal approximation makes sense.

Since the calculated value is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level provided and we can conclude that the true proportion is lower than 0.76

6 0

4 years ago

|5c -3|= 1<br> Solve for C (this is homework help-)

irina [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

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