Solve in equality and show all your steps by algebraic symbols <br><br> 3 + 16x >

If a fair die is rolled 4 times, what is the probability, to the

Natalka [10]

Answer:

1/6 · $10^{1000}$

Step-by-step explanation:

4 0

3 years ago

Find the value of x 55+(x+25)=180

s344n2d4d5 [400]

55+(x+25)=180
55+x+25=180
25+55+x=180
80+x=180
x=180-80
x=100

5 0

3 years ago

A pie is cut into eight pieces.at what acute angle is each piece cut?

Dahasolnce [82]

I really don't now but a pie is a circle right and a circle is 360 degrees. So would it be 360 ÷ 8 = 45

5 0

4 years ago

the Johnsons want to cover their backyard with new grass their backyard is rectangular with a length of 3x - 2 feet and a width

Andre45 [30]

<h2>Hello!</h2>

The answer is:

The area that the want to cover with new grass will be:

$Area_{grass}=8x^{2} -12x-22$

If we want to calculate what is the ara of the region of the backyard that they want to cover with new grass, we need to calculate the area of the backyard, calculate the area of the swimming pool and its patio, and the last step is to subtract the area of the swimming pool and its patio to the total area of the backyard.

So, to calculate the areas, we need to use the following formula:

$Area=Length*Width$

Also, we need to remember how the distributive property works, since we are going to need it.

We have that:

$(a+b)(c+d)=ac+ad+bc+bd$

We are given the following information:

For the backyard we have:

$Length=3x-2\\Width=3x+1$

For the swimming pool and its patio:

Since there it's not mentioned, let be the first expression the length, and the second one, the width.

$Length=x+4\\Width=x+5$

Then, calculating we have:

Backyard:

$Area_{backyard}=(3x-2)*(3x+1)=9x^{2}+3x-6x-2=9x^{2}-3x-2$

Swimming pool and patio:

$Area_{swimmingpool}=(x+4)*(x+5)=x^{2}+5x+4x+20=x^{2}+9x+20$

Now, calculating the area that they want to cover with new grass, we have:

$Area_{grass}=Area_{backyard}-Area_{swimmingPool}\\\\Area_{grass}=(9x^{2}-3x-2)-(x^{2}+9x+20)\\\\Area_{grass}=9x^{2} -x^{2} -3x-9x-2-20\\\\Area_{grass}=8x^{2} -12x-22$