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lilavasa [31]
3 years ago
11

I need help with this. I do not understand it.

Mathematics
2 answers:
miv72 [106K]3 years ago
6 0
41.75 hours.

To get this answer just add all of the numbers for week 5/10.
crimeas [40]3 years ago
6 0
41.75 hr ............
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6 to the second power ÷ [(4.3×3)+5.1]
Black_prince [1.1K]
2 is the answer
That’s the answer.
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3 years ago
Evaluate −x^2−5 y^3 when x = 4 and y = 1
Natali [406]

Answer:

Simplify:

-4^2-5(1^3)

So you get:

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4 0
3 years ago
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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
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Scrat [10]

Answer:

10

Step-by-step explanation:

The lines surrounding 10 are called positive brackets, meaning the no matter what number is in those brackets, it will always come out of positive.

There is nothing to do with just 10 because we don't need to change anything.

|10| simplified is 10

5 0
3 years ago
Write down two factors of 18
frutty [35]

Answer:

Any two factors of 18 2 ,3

7 0
3 years ago
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