I think the blanks would be, "sides" and "angles."
In order to prove this, you simply plug in the number 2 everywhere you see X:
4^(2) = 8(2).
Simplify
16 = 16 √
Since this checks out, x is proven to be 2.
The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
Learn more about extraneous solution on:
brainly.com/question/295656
#SPJ4
Answer:
1 hour 9 minutes
Step-by-step explanation:
Answer: Help with what
Step-by-step explanation:1 + 1 = 2