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Serga [27]
3 years ago
8

Please help me with this problemplssssssssssss

Mathematics
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

The solution is: x = -5.2, y = 11.2

Step-by-step explanation:

We are given the following system of equations:

-7x-2y = 14

6x + 6y = 18

Simplifying the second equation by three, we have that:

x + y = 6

y = 6 - x.

Replacing in the first equation:

-7x - 2(6 - x) = 14

-7x - 12 + 2x = 14

-5x = 26

5x = -26

x = -5.2

y = 6 - x = 6 - (-5.2) = 6 + 5.2 = 11.2

The solution is: x = -5.2, y = 11.2

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4 0
3 years ago
find the equation of a line through the coordinate (3,6) and parallel to the line represented by y=5/3 x-1
maw [93]

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0 or (0,y))


For lines to be parallel, their slopes have to be the SAME.


The given line's slope is 5/3, so the parallel line's slope is also 5/3

y = 5/3x + b

To find "b", plug in the point (3,6) into the equation

y = 5/3x + b

6 = 5/3(3) + b

6 = 5 + b

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5 0
3 years ago
What is the relationship between the measure of an angle and the reflex measure of the angle?
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3 0
3 years ago
Solve the equation cot 2x + cot x =3
rusak2 [61]

tan2x*cotx - 3 = 0

We know that: tan2x = sin2x/cos2x and cotx = cosx/sinx

==> sin2x/cos2x *cosx/sinx = 3

Now we know that sin2x = 2sinx*cosx

==> 2sinxcosx/cos2x * cosx/sinx = 3

Reduce sinx:

==> 2cos^2 x/ cos2x = 3

Now we know that cos2x = 2cos^2 x-1

==> 2cos^2 x/(2cos^2 x -1) = 3

==> 2cos^2 x = 3(2cos^2 x -1)

==> 2cos^2 x = 6cos^2 x - 3

==> -4cos^2 x= -3

==> 4cos^2 x = 3

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==> cosx = +-sqrt3/ 2

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3 0
3 years ago
1. Find m2K.
Kruka [31]

Answer:

m∠k = 60°

Step-by-step explanation:

  • an exterior angle of a triangle is equal to the sum of the opposite interior angles

4x + 2 + 6x - 12 = 130

to find x:

4x + 2 + 6x - 12 = 130

4x + 6x = 130 - 2 + 12

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x = 120/10

x = 12

apply the value of x to find the measure of angle K:

k = 6*12 - 12 = 60

5 0
3 years ago
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