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Blizzard [7]
3 years ago
9

Janet's dog weighs 18.2 pounds Charlie's dog is 7.4 pounds about how much does Janet's dog weigh than Charlies

Mathematics
2 answers:
Goshia [24]3 years ago
8 0

Answer:

Step-by-step explanation:

10.8

nadezda [96]3 years ago
4 0

Answer:

Janet's dog weighs 10.8 pounds more

Step-by-step explanation:

   

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Phoebe compared the cost of books in 9 different stores.
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You have to put the numbers in order and find the middle value so in this case it's-

2, 4, 4, 5, 6, 7, 8, 8, 8 

The answer is $6
7 0
3 years ago
Find the greatest common factor of 15x^2y^3 and -20x^3yz
zaharov [31]
5x^2y is the greatest common factor
4 0
3 years ago
PLZ I NEED HELP THIS IS PART OF A TEST
shepuryov [24]

Answer:

6.25 inches

Step-by-step explanation:

25/4=6.25

4 0
3 years ago
Read 2 more answers
The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).
lesantik [10]

Answer:

(a).

S_{n} =  \frac{n}{2} (4n + 20) \\  \\S _{n - 1} =  \frac{(n - 1)}{2} (4n - 4 + 20) \\  \\ S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16) \\  \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2}  \\   \\  { \boxed{S _{n - 1} =  {2 {n}^{2} + 6n - 8}}} \\

(b).

from general equation:

S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16)

first term is 4n

common difference:

16 =  \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d =  \frac{16}{n - 2}

8 0
3 years ago
Bobby has already ran 1 mile on his own, and he expects to run 1 mile during each track practice. How many track practices would
german

Answer:

In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>

Step-by-step explanation:

Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.

You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.

Setting up an equation will help us solve. Here is how we could set up the equation:

(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)

1 + x = 33

The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.

1 + x = 33

1 - 1 + x = 33 - 1

x = 32

The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.

8 0
3 years ago
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