Answer:
∑ (-1)ⁿ⁺³ 1 / (n^½)
∑ (-1)³ⁿ 1 / (8 + n)
Step-by-step explanation:
If ∑ an is convergent and ∑│an│is divergent, then the series is conditionally convergent.
Option A: (-1)²ⁿ is always +1. So an =│an│and both series converge (absolutely convergent).
Option B: bn = 1 / (n^⁹/₈) is a p series with p > 1, so both an and │an│converge (absolutely convergent).
Option C: an = 1 / n³ isn't an alternating series. So an =│an│and both series converge (p series with p > 1). This is absolutely convergent.
Option D: bn = 1 / (n^½) is a p series with p = ½, so this is a diverging series. Since lim(n→∞) bn = 0, and bn is decreasing, then an converges. So this is conditionally convergent.
Option E: (-1)³ⁿ = (-1)²ⁿ (-1)ⁿ = (-1)ⁿ, so this is an alternating series. bn = 1 / (8 + n), which diverges. Since lim(n→∞) bn = 0, and bn is decreasing, then an converges. So this is conditionally convergent.
Answer:
I think It might be A
Step-by-step explanation:
Don't trust me tho
Answer:
All real numbers except where x<-3
Step-by-step explanation:
Values of x that make negatives under even radicals are not part of the domain. Any value of x that is less than -3 would make a negative under the square root, so those are not included in the domain.
Answer:
12
Step-by-step explanation:
12 = 2 digits
1 + 2 = 3
1 < 2
The first digit may be 1 or 8.
The second digit may be 1, 2, 4, 8.
The third digit may be 1, 3, 5, 7, 9.
There are 
The probability that this is the correct code is 
