Answer:
Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula
Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:
We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:
Let's build up the polynomial, assuming a=1:
Since:
Operating the last two factors:
Operating, we have the required polynomial:
Let the weight of triangle be x units. You are given that the weight of square is 1 unit.
1) On the left side of the balanced beam you can see 3 triangles and 5 squares. The weight on left side is 3·x+5·1=3x+5 units.
2) On the right side of the balanced beam you can see 2 triangles and 7 squares. The weight on right side is 2·x+7·1=2x+7 units.
3) If the whole system is balanced, then the weights on left and right sides are equal:
3x+5=2x+7.
Solve this equation:
3x-2x=7-5,
x=2 units.
Answer: option A
Answer:
10.7
Step-by-step explanation:
add multiple than subtract what you multiple and add a decimal
Answer:
you forgot to add the statements
Answer:
Hi hope you have a wonderful and blessed day!!!!
Step-by-step explanation:
