The surface area of the cone is given by:
![SA=\pi r^2+\pi Lr](https://tex.z-dn.net/?f=SA%3D%5Cpi%20r%5E2%2B%5Cpi%20Lr)
where r is the radius and L is slant height.
In this case r=5 and L=12. Then the surface area is:
![\begin{gathered} SA=(3.14)(5)^2+(3.14)(12)(5) \\ =267 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20SA%3D%283.14%29%285%29%5E2%2B%283.14%29%2812%29%285%29%20%5C%5C%20%3D267%20%5Cend%7Bgathered%7D)
Therefore the surface area is 267 squared centimeters,
For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
In this case we have the following equation of the line:
![y = -6x + 5](https://tex.z-dn.net/?f=y%20%3D%20-6x%20%2B%205)
Where:
![m = -6](https://tex.z-dn.net/?f=m%20%3D%20-6)
By definition, if two lines are parallel then their slopes are equal. Thus, a parallel line will have an equation of the form:
![y = -6x + b](https://tex.z-dn.net/?f=y%20%3D%20-6x%20%2B%20b)
Substitute the given point
to find "b":
![4 = -6 (4) + b\\4 = -24 + b\\4 + 24 = b\\b = 28](https://tex.z-dn.net/?f=4%20%3D%20-6%20%284%29%20%2B%20b%5C%5C4%20%3D%20-24%20%2B%20b%5C%5C4%20%2B%2024%20%3D%20b%5C%5Cb%20%3D%2028)
Finally, the equation of the requested line is:
![y = -6x + 28](https://tex.z-dn.net/?f=y%20%3D%20-6x%20%2B%2028)
Answer:
![y = -6x + 28](https://tex.z-dn.net/?f=y%20%3D%20-6x%20%2B%2028)
We can input the point
remember that (x,y)
so we are given (-5,-18)
so when x=-5, y=-18
so
-18=-5m+2
minus 2 both sides
-20=-5m
divide both sides by -5
4=m
m=4
answer is 2nd option
{3, 1, -1, -2,-5} bc each point is has a x and y (x,y) domain is listing the x’s so that’s how you get your answer