1) 6, 18, 54
2) 5/3, 14/9, 41/27
3) 1.5, 2.5, 2.5
Step-by-step explanation:
1)
The function that we have in this problem is
![g(x)=3x](https://tex.z-dn.net/?f=g%28x%29%3D3x)
We want to find the first 3 iterations.
The initial value is:
x = 2
To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:
![g_1(x)=3x=3\cdot 2 = 6](https://tex.z-dn.net/?f=g_1%28x%29%3D3x%3D3%5Ccdot%202%20%3D%206)
The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:
![g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18](https://tex.z-dn.net/?f=g_2%28x%29%3D3%5Ccdot%20g_1%28x%29%3D3%5Ccdot%206%20%3D%2018)
Finally, the 3rd iteraction is given by:
![g_3(x)=3g_2(x)=3\cdot 18=54](https://tex.z-dn.net/?f=g_3%28x%29%3D3g_2%28x%29%3D3%5Ccdot%2018%3D54)
2)
Here in this problem the function that we have to use is
![g(x)=\frac{1}{3}x+1](https://tex.z-dn.net/?f=g%28x%29%3D%5Cfrac%7B1%7D%7B3%7Dx%2B1)
The initial value is
![x=2](https://tex.z-dn.net/?f=x%3D2)
So the first iteration is given by
![g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}](https://tex.z-dn.net/?f=g_1%28x%29%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot%202%20%2B%201%20%3D%20%5Cfrac%7B5%7D%7B3%7D)
To find the 2nd iteration, we substitute this value into g(x) again:
![g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}](https://tex.z-dn.net/?f=g_2%28x%29%3D%5Cfrac%7B1%7D%7B3%7Dg_1%2B1%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot%20%5Cfrac%7B5%7D%7B3%7D%2B1%3D%5Cfrac%7B5%7D%7B9%7D%2B1%3D%5Cfrac%7B14%7D%7B9%7D)
Finally, to find the 3rd iteration, we substitute this value into g(x) again:
![g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}](https://tex.z-dn.net/?f=g_3%28x%29%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot%20%5Cfrac%7B14%7D%7B9%7D%2B1%3D%5Cfrac%7B14%7D%7B27%7D%2B1%3D%5Cfrac%7B41%7D%7B27%7D)
3)
The function in this problem is
![g(x)=-|x-2|+3](https://tex.z-dn.net/?f=g%28x%29%3D-%7Cx-2%7C%2B3)
The initial value is
x = 0.5
So, the first iteration is:
![g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5](https://tex.z-dn.net/?f=g_1%28x%29%3D-1%7C0.5-2%7C%2B3%3D-1%7C-1.5%7C%2B3%3D-1%5Ccdot%201.5%20%2B3%3D-1.5%2B3%3D1.5)
The second iteration is given by
![g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5](https://tex.z-dn.net/?f=g_2%28x%29%3D-%7Cg_1-2%7C%2B3%3D-%7C1.5-2%7C%2B3%3D--0.5%2B3%3D2.5)
Finally, the 3rd iteration is
![g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5](https://tex.z-dn.net/?f=g_3%28x%29%3D-%7Cg_2-2%7C%2B3%3D-%7C2.5-2%7C%2B3%3D-0.5%2B3%3D2.5)