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3 years ago

Thank you so much for helping meeeeee

Mathematics

1 answer:

Ivenika [448]3 years ago

7 0

Hello, and thanks for posting your question!

A function would be a set of ordered pairs that have no repeating "x" values, look at the example below. (V)

{(1, 0), (2, 0), (3, 0)} = Function
{(1, 0), (1, 0), (2, 0)} = Not a function.

According to this information, your answer is C. Both Set A and Set B.

Hope this helps! ☺♥

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Evaluate 5(x + y)2 when x = 3 and y = 9

irakobra [83]

Hey there!

$Answer:\boxed{120}$

$Explanation:$

$5(x+y)2$ when x = 3 and y = 9

Let's first move to x and y.

$x=3\\y=9\\3+9=12$

Now multiply 5 by x and y(3+9).

$5*12(\text{x and y combined)}=60$

Now we have the number 2 left, so we have to multiply 60 by 2.

$60*2=120$

$\boxed{120}\text{ is your final answer.}$

Hope this helps!

$\text{-TestedHyperr}$

4 0

3 years ago

John borrowed $1200 from his credit union at 18% simple interest. He agrees to repay the loan by making

kakasveta [241]

1200 (1+.8 * 30/12) = 1740.00
1740.00 - 1200 = $540

4 0

2 years ago

Shelly biked 21 miles in 4 hours. What is Shelly average speed in miles per hour

Maksim231197 [3]

To solve this, you would divide the miles by the number of hours, 21 / 4
21 divided by 4 equals 5.25

3 0

2 years ago

Read 2 more answers

Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6

crimeas [40]

Answer:

c. 3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

$\dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}$

3 0

2 years ago

A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand

sesenic [268]

Answer:

The 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =80$ represent the sample mean 1

$\bar X_2 =75$ represent the sample mean 2

n1=25 represent the sample 1 size

n2=36 represent the sample 2 size

$\sigma_1 =5$ sample standard deviation for sample 1

$\sigma_2 =3$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =80-75=5$

Since the Confidence is 0.94 or 94%, the value of $\alpha=0.06$ and $\alpha/2 =0.03$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that $z_{\alpha/2}=1.88$