6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1
6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5
Answer: the required probability is 0.03516
Step-by-step explanation:
Given the data in the question;
let F represent dominant allele that causes fluffy fur and
f represent corresponding recessive allele that causes wiry fur
here are the possible genotypes and corresponding phenotypes;
FF = Fluffy fur
Ff = Fluffy fur
ff = Wiry fur
genotype of parents is Ff and Ff
and there cross will be; Ff x Ff
now Offspring will be;
F f
F FF Ff
f Ff ff
so the probability that the offspring will have fluffy fur = 3/4
and the probability that the offspring will have wiry fur = 1/4
The probability that the first 2 out of 4 offspring will have fluffy fur will be;
⇒ 3/4 × 3/4 × 1/4 × 1/4 = 0.03516
Therefore, the required probability is 0.03516
Answer:
3, 2, 1, 0, literally anything below 4
Step-by-step explanation:
The "mouth" < or > eats the bigger number, if 4 is bigger than x, x must be smaller than 4
