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3 years ago

Which value is a solution to the inequality x < 4

Mathematics

1 answer:

denpristay [2]3 years ago

5 0

Answer:

3, 2, 1, 0, literally anything below 4

Step-by-step explanation:

The "mouth" < or > eats the bigger number, if 4 is bigger than x, x must be smaller than 4

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A 6 oz paper cup is shaped like a cone with a diameter of 4 inches. How many ounces of water will a plastic cylindrical cup with

OleMash [197]

Answer:

The plastic cylindrical cup will hold 17.96 ounces of water.

Step-by-step explanation:

Given:

A 6 oz paper cup is shaped like a cone with a diameter of 4 inches.

Now, to find ounces of water will a plastic cylindrical cup with a diameter of 4 inches hold if it is the same height as the paper cup.

Volume of cone = 6 oz.

Diameter = 4 inches.

So, radius (r) = $\frac{Diameter}{2} =\frac{4}{2} =2\ inches.$

Taking the value $\pi$ = 3.14.

Now, to get the height (h) we put formula:

$Volume=\pi r^2\frac{h}{3}$

$Volume=3.14\times 2^2\times \frac{h}{3}$

$6=3.14\times 4\times \frac{h}{3}$

Multiplying both sides by 3 we get:

$18=12.56h$

Dividing both sides by 12.56 we get:

$1.43=h$

$h=1.43\ inches.$

Now, to get the volume of cylindrical cup.

As, given it is the same height as the paper cup.

Height (h) = 1.43 inches.

Diameter = 4 inches.

Radius (r) = $\frac{Diameter}{2} =\frac{4}{2} =2\ inches.$

So, we put formula to get the ounces of water a plastic cylindrical cup will hold:

$Volume =\pi r^2h$

$Volume=3.14\times 2^2\times 1.43$

$Volume=3.14\times 4\times 1.43$

$Volume=17.96\ oz.$

Therefore, the plastic cylindrical cup will hold 17.96 ounces of water.

5 0

3 years ago

What is #3? I need to know.

MissTica

Answer huh?

Step-by-step explanation:

5 0

3 years ago

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Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

Write an expression for the volume of a rectangular prism with length 7.5 ft, width w ft, and height 4.2 ft. Enter the smaller n

valkas [14]

Answer:

Step-by-step explanation:

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3 years ago

The formula for the circumference of a circle is C = 2r, where r is the radius and C is the circumference. The equation solved f

Lubov Fominskaja [6]

Answer:

r = c/2pi

Step-by-step

c= pi*d

d=2r

c = 2*r*pi

6 0

3 years ago

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