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3 years ago

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Can someone please help me find the range

1 answer:

defon3 years ago

4 0

Answer:

Step-by-step explanation

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Four less than the quotient of a number 2 and 5.

Papessa [141]

Answer:

2/5 - 4

Step-by-step explanation:

quotient means to divide

4 less means subtraction

8 0

2 years ago

Evaluate C(44,21) use scientific notation, round to 3 decimal places as needed.

STALIN [3.7K]

$C(44,21)=\dfrac{44!}{21!23!}=\dfrac{24\cdot25\cdot\ldots\cdot43\cdot44}{2\cdot3\cdot\ldots\cdot 20\cdot21}=2,012,616,400,080\\
\approx2.013\cdot10^{12}$

6 0

3 years ago

1. Solve for w in the equation W/5 = 25<br> A.W = 5<br> B.W = 125<br> C. W = 30<br> D.W = 20

vekshin1

Answer: <em>w = 125</em>

Explanation: Since <em>w</em> is being divided by 5, to solve for <em>w</em>,

multiply both sides of the equation by 5.

On the left side, the 5's will cancel

and on the right side, 25(5) is 125.

So <em>w = 125</em>.

<u />

<u>Please do not do this problem in your head.</u>

Show the work that it takes to get <em>w</em> by itself.

3 0

3 years ago

When the members of a family discussed where their annual reunion should take place, they found that out of all the family mem

Doss [256]

Answer:

The total number of family members is 21.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these sets.

I am going to say that:

-The set A represents those that would not go to a park.

-The set B represents those who would not go to a beach.

-The set C represents those who would not go to the family cottage.

The value d represents those who would go to all three places.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a are those that would only not go to a park, $A \cap B$ are those who would not got to a park or to the beach, $A \cap C$ are those who would not go to a park or to the famili cottage. And $A \cap B \cap C$ are those that would not go to any of these places.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following values:

$a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

The total number of family members is the sum of all these values:

$T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

We start finding the values from the intersection of the three sets

5 would not go to a park or a beach or to the family cottage.

This means that $A \cap B \cap C = 5$

1 would go to all three places. This means that $d = 1$ .

8 would go to neither a park nor the family cottage

This means that:

$A \cap C + (A \cap B \cap C) = 8$

$A \cap C = 3$

8 would go to neither a beach nor the family cottage

$B \cap C + (A \cap B \cap C) = 8$

$B \cap C = 3$

7 would go to neither a park nor a beach

$A \cap B + (A \cap B \cap C) = 7$

$A \cap B = 2$

15 would not go to the family cottage

$C = 15$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$15 = c + 3 + 3 + 5$

$c = 4$

12 would not go to a beach

$B = 12$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$12 = b + 3 + 2 + 5$

$b = 2$

11 would not go to a park

$A = 11$

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

$11 = a + 2 + 3 + 5$

$a = 1$

Now, we can find the total number of family members.

$T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$T = 1 + 2 + 4 + 1 + 2 + 3 + 3 + 5$

$T = 21$

The total number of family members is 21.

5 0

3 years ago

(x+6)(x+3) = x(x+6)+(x+6)(3)<br> Whats the froof here ?

natulia [17]

Answer:

I'm confused as you are

4 0

3 years ago

Read 2 more answers